10(x)=3x^2

Solution for 10(x)=3x^2 equation:

10(x)=3x^2

We move all terms to the left:

10(x)-(3x^2)=0

determiningTheFunctionDomain
-3x^2+10x=0

a = -3; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-3)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-3}=\frac{-20}{-6}
=3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-3}=\frac{0}{-6}
=0
$